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0=-0.5x^2+1.5x+2
We move all terms to the left:
0-(-0.5x^2+1.5x+2)=0
We add all the numbers together, and all the variables
-(-0.5x^2+1.5x+2)=0
We get rid of parentheses
0.5x^2-1.5x-2=0
a = 0.5; b = -1.5; c = -2;
Δ = b2-4ac
Δ = -1.52-4·0.5·(-2)
Δ = 6.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{6.25}}{2*0.5}=\frac{1.5-\sqrt{6.25}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{6.25}}{2*0.5}=\frac{1.5+\sqrt{6.25}}{1} $
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